In a fission reaction _{92}^{236}U to ^{117}X | vedclass

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(C) The energy released in a nuclear fission reaction is given by the difference between the total binding energy of the products and the total bindin

Vedclass · Accepted Answer

$200\, MeV$

Vedclass · Answer

(C) The energy released in a nuclear fission reaction is given by the difference between the total binding energy of the products and the total binding energy of the reactants.Total binding energy of reactants = $236 	imes 7.6\, MeV = 1793.6\, MeV$.Total binding energy of products = $(117 	imes 8.5\, MeV) + (117 	imes 8.5\, MeV) = 234 	imes 8.5\, MeV = 1989\, MeV$.Energy liberated = $	ext{Total binding energy of products} - 	ext{Total binding energy of reactants}$.Energy liberated = $1989\, MeV - 1793.6\, MeV = 195.4\, MeV$.Rounding this value,the total energy liberated is approximately $200\, MeV$.

In a fission reaction $_{92}^{236}U \to ^{117}X + ^{117}Y + n + n$,the binding energy per nucleon of $X$ and $Y$ is $8.5\, MeV$,whereas that of $^{236}U$ is $7.6\, MeV$. The total energy liberated will be about:

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